If you’re still in the ball game, your chance of getting the second roll you need for an 11 is again 16, so the total chance that you will roll an 11 is 13⋅16=118. Adding these two independent probabilities, the chance of rolling either a 7 or 11 is 16+118=29.

## What is the probability of getting a sum of 11 when two dice are rolled?

Probabilities for the two dice

Total | Number of combinations | Probability |
---|---|---|

10 | 3 | 8.33% |

11 | 2 |
5.56% |

12 | 1 | 2.78% |

Total | 36 | 100% |

## What is the probability of getting a total of 7 or 11 when rolling 2 dice?

What is the probability that the sum will be a 7 or 11? There are 36 possible outcomes for the two dice. So, the probability is **8/36 = 2/9**.

## What is the probability of rolling a sum of 5 or a sum of 11?

As Steve says the probability of rolling a 5 is 4/36 and the probability of rolling ian 11 is **2/36** so the probability of rolling neither is 1 – (2/36 + 4/36) = 30/36.

## What is the probability of 3 dice?

Two (6-sided) dice roll probability table

Roll a… | Probability |
---|---|

3 | 3/36 (8.333%) |

4 | 6/36 (16.667%) |

5 | 10/36 (27.778%) |

6 | 15/36 (41.667%) |

## What is the probability of getting a sum of 11 2 between 7 and 12?

The probability is **25%** .

## What is the probability of rolling a total of 7 on two dice?

For each of the possible outcomes add the numbers on the two dice and count how many times this sum is 7. If you do so you will find that the sum is 7 for 6 of the possible outcomes. Thus the sum is a 7 in 6 of the 36 outcomes and hence the probability of rolling a 7 is **6/36 = 1/6**.

## When two dice are rolled what is the probability?

If the die is fair (and we will assume that all of them are), then each of these outcomes is equally likely. Since there are six possible outcomes, the probability of obtaining any side of the die is **1/6**. The probability of rolling a 1 is 1/6, the probability of rolling a 2 is 1/6, and so on.

## What is the probability that the sum are 5 and 7?

That’s not exactly right because the true probability is that MINUS the probability of getting both a sum of 5 and a sum of 7. In other words, the answer = p(sum of 5) + p(sum of 7) – p(sum of 5 and sum of 7) , which equals p(1–4, 4–1, 2–3, 3–2) + p(1–6, 6–1, 2–5, 5–2, 3–4, 4–3) – 0 = **10/36** or 5/18.

## What is the probability that the product will be 5?

The probability is **2/36 or 1/18**. The only two numbers that give a product of 5 is 1×5. Since there are 36 numbers from a pair of dice, and there are two ways rolling a 5 and a 1 of the probability is 2/36 or 1/18.